A spring has a relaxed length of 6 cm and a stiffness of 200 N/m. How much work must you do to change its length from 9 cm to 14 cm?How much work must you do to change its length from 9 cm to 14 cm?
Find the spring potential energy at both lengths.
SPE1 = 1/2*k*(L1-L0)^2
SPE2 = 1/2*k*(L2-L0)^2
W = SPE2 - SPE1
W = 1/2*k*(L2-L0)^2 - 1/2*k*(L1-L0)^2
Simplify:
W = 1/2*k*((L2 - L0)^2 - (L1-L0)^2)
Plug in data:
k:=200 N/m; L0 := 0.06 m; L1:=0.09 m; L2:=0.14m;
Result:
W = 0.55 JoulesHow much work must you do to change its length from 9 cm to 14 cm?
Solution
K = 200N/m
Change in length = 14 ?9 = 5cm = 0.05m
F = Kx
F = (200) (0.05)
F = 10N
Now using
W = F.X
W = (10) (0.05)
W = 0.5Joules
So you have to perform 0.5 Joules of work on the spring in order to change its length from 9 cm to 14 cm.
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