This is related to the marble launcher problem, posted earlier.?

When a spring is pulled back at a certain Constant distance, can the amount of force added and how fast you pull it to the distance, change the force that the spring exerts?This is related to the marble launcher problem, posted earlier.?
No.



E=1/2kx^2, where x is the displacement of the spring from its equilibrium position. This elastic potential energy is then converted to kinetic energy with E=1/2mv^2.



so we have



kx^2 = mv^2



v = sqrt(k/m)*x



Where v is the speed, k is the spring constant, m is the mass of the object you're launching, and x is the distance you stretch the spring by from its equilibrium position.



As you can see, this equation has nothing to do with how fast you stretch it or how hard you stretch it. The only thing that matters is the amount you stretch it by.